题解 | #二叉树的后序遍历#
二叉树的后序遍历
https://www.nowcoder.com/practice/1291064f4d5d4bdeaefbf0dd47d78541
/** * struct TreeNode { * int val; * struct TreeNode *left; * struct TreeNode *right; * }; */ /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param root TreeNode类 * @return int整型一维数组 * @return int* returnSize 返回数组行数 */ void postorderTraversalHelper(struct TreeNode* root, int* arr, int* returnSize) { if(root == NULL) return; postorderTraversalHelper(root->left, arr, returnSize); postorderTraversalHelper(root->right, arr, returnSize); arr[(*returnSize)++] = root->val; } int* postorderTraversal(struct TreeNode* root, int* returnSize ) { // write code here int* arr = (int*)malloc(sizeof(int) * 100); (*returnSize) = 0; postorderTraversalHelper(root, arr, returnSize); return arr; }