题解 | #时间转换#

#include<stdio.h>
int main()
{
    int seconds;
    int s=0;
    int h=0;
    int m=0;
    int a=0;
    scanf ("%d\n",&seconds);
    if (seconds>0&&seconds<100000000)
    {
        a=(seconds-seconds%60)/60;
        s=seconds%60;        
        h=(a-a%60)/60;
        m=(seconds-h*3600-s)/60;
    printf ("%d %d %d\n",h,m,s);
    }
    return 0;
}