题解 | #有序序列判断#
有序序列判断
https://www.nowcoder.com/practice/22e87f8a8d764a6582710f38d1b40c6e
#include <stdio.h>
int main()
{
int n = 0, flag = 0;
scanf("%d", &n);
int arr[50] = { 0 };
for (int i = 0;i < n;i++)
scanf("%d", &arr[i]);
for (int i = 0;i < n;i++)
{
for (int j = i + 1;j < n;j++)
if (arr[i] > arr[j])
{
flag++;
}
}
if (flag == 0 || flag == n * (n - 1) / 2)
printf("sorted");
else
printf("unsorted");
return 0;
}
//比较抽象,通过逐个两个相比统计左大于右的次数