题解 | #从单向链表中删除指定值的节点#

from os import remove

while 1:
    try:
        l=list(map(int,input().split()))
        n=l[0]
        l_list=[l[1]]
        note=[]
        for i in range(1,n):
            a=l[2*i:2*(i+1)]
            note.append(a)
            for j in l_list:
                if j==a[1]:
                    l_list[(l_list.index(j)+1):(l_list.index(j)+1)]=[a[0]]
        del_note=l[-1]
        l_list.remove(del_note)
        for i in l_list:
            print(i,end=' ')

    except:
        break