题解 | #字符串操作#

#include <stdio.h>
# pragma warning(disable:4996)
void jiaohuan(char* c, int l, int r, char c1, char c2);
int main() {
    int n, m, i, l, r;
    char c1, c2;
    char c[100];
    scanf("%d %d", &n, &m);
    scanf("%s", c);
    for (i = 1; i <= m; i++) {
        scanf("%d %d %c %c", &l, &r, &c1, &c2);
        jiaohuan(c, l, r, c1, c2);
    }
    printf("%s", c);
    return 0;
}
void jiaohuan(char* c, int l, int r, char c1, char c2) {
    int t;
    for (t = l - 1; t < r; t++) {
        if (c[t] == c1)
            c[t] = c2;
    }
}