题解 | #从单向链表中删除指定值的节点#

inData = input().split()

linkedList = [inData[1]]

for i in range(2, int(inData[0])*2, 2):
    n = inData[i]
    t = inData[i+1]
    l = linkedList.index(t)
    linkedList.insert(l+1, n)

linkedList.remove(inData[-1])

print(" ".join(linkedList))