题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
inData = input().split()
linkedList = [inData[1]]
for i in range(2, int(inData[0])*2, 2):
n = inData[i]
t = inData[i+1]
l = linkedList.index(t)
linkedList.insert(l+1, n)
linkedList.remove(inData[-1])
print(" ".join(linkedList))
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