简单密码#ascii码ord() chr()

简单密码

https://www.nowcoder.com/practice/7960b5038a2142a18e27e4c733855dac

'''
print(ord('a'),ord('b'),ord('A'),ord('B'))
print(chr(97),chr(98),chr(65),chr(66))
print('A'.lower())
mapping={0:0,1:1,'abc':2,'def':3,'ghi':4,'jkl':5,'mno':6,'pqrs':7,'tuv':8,'wxyz':9}
print(mapping.items())
print(mapping.keys(),mapping.values())
print('s' in list(mapping.keys())[9])
'''

pw=str(input())
#mapping={0:0,1:1,2:'abc',3:'def',4:'ghi',5:'jkl',6:'mno',7:'pqrs',8:'tuv',9:'wxyz'}
#print(mapping.keys,mapping.values)
mapping=['0','1','abc','def','ghi','jkl','mno','pqrs','tuv','wxyz'] # 
new_pw=''
for i in pw:
    if 65<=ord(i)<=89:
        new_pw += chr(ord(i.lower())+1)
    elif ord(i)==90:
        new_pw += 'a'
    elif 97<=ord(i)<=122:
        for j in mapping:
            if i in j:
                new_pw += str(mapping.index(j))
    else:
        new_pw += i
print(new_pw)
        

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