题解 | #不相邻取数#
不相邻取数
https://www.nowcoder.com/practice/a2be806a0e5747a088670f5dc62cfa1e
#include <iostream>
using namespace std;
const int N = 2 * 100010;
int a[N], f[N];
int main() {
int n;
cin >> n;
for(int i = 1; i <= n; i ++) cin >> a[i];
f[1] = a[1];
for(int i = 2; i <= n; i ++){
f[i] = max(f[i - 2] + a[i], f[i - 1]);
}
cout << f[n] << endl;
}
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