题解 | #字符串通配符#

s1 = input()
s2 = input()
m = len(s1)
n = len(s2)
dp = [[False for j in range(n + 1)] for i in range(m + 1)]
dp[0][0] = True
# 处理第0行()
for j in range(1, n + 1):
    dp[0][j] = False
# 处理第0列(特别注意第0列的处理方式)
for i in range(1, m + 1):
    if s1[i - 1] == "*":
        dp[i][0] = True
    else:
        break
# 处理其他值
for i in range(1, m + 1):
    for j in range(1, n + 1):
        if s1[i - 1].lower() == s2[j - 1].lower():  # 注意这里一定统一大写或者统一小写，才好比较（不区分时会报错）
            dp[i][j] = dp[i - 1][j - 1]
        if s1[i - 1] == "?" and s2[j - 1].isalnum():  # isalnum()表示所有字符均为字母或者数字
            dp[i][j] = dp[i - 1][j - 1]
        if s1[i - 1] == "*":
            dp[i][j] = dp[i - 1][j] or dp[i][j - 1]
if dp[m][n]:
    print("true")
else:
    print("false")