题解 | #简单密码#

# 收集原始密码
password_input = input()

# 将字母和数字进行mapping
keypad_mapping = {
    'a': '2', 'b': '2', 'c': '2',
    'd': '3', 'e': '3', 'f': '3',
    'g': '4', 'h': '4', 'i': '4',
    'j': '5', 'k': '5', 'l': '5',
    'm': '6', 'n': '6', 'o': '6',
    'p': '7', 'q': '7', 'r': '7', 's': '7',
    't': '8', 'u': '8', 'v': '8',
    'w': '9', 'x': '9', 'y': '9', 'z': '9',
    '0': '0', '1': '1', '2': '2', '3': '3','4': '4', '5': '5', '6': '6', '7': '7','8': '8', '9': '9'
}

# 初始化一个空的string
transformed_password = ''

# 将input中每个字符都循环一遍
for char in password_input:
    if char.islower():  # If the character is lowercase
        transformed_password += keypad_mapping[char]  # Map directly to number
    elif char.isupper():  # If the character is uppercase
        if char == 'Z':
            transformed_password += 'a'  # Wrap 'Z' to 'a'
        else:
            next_char = chr(ord(char.lower()) + 1)  # Convert to lowercase and shift
            transformed_password += next_char
    else:
        transformed_password += char  # Leave digits and other characters unchanged

# 输出加密后代码
print(transformed_password)