题解 | #公共子串计算#
公共子串计算
https://www.nowcoder.com/practice/98dc82c094e043ccb7e0570e5342dd1b
s1 = input().lower()
s2 = input().lower()
p = 0
if len(s1) > len(s2):
s1, s2 = s2, s1
for i in range(len(s1)):
for j in range(i, len(s1)):
if s1[i : j + 1] in s2 and j + 1 - i > p:
p = j + 1 - i
print(p)
