题解 | #降温（hard）#

快速IO，然后用if-else分别模拟求出最大最小值即可

from sys import stdin, stdout
def main():
    input = stdin.readline
    n,x = map(int,input().split())
    if n == 1:
        print("0 0")
        return
    l = [int(i) for i in input().split()]
    cntmax = 0
    cntmin = 0
    # cntmax
    if l[0] != -999999999:
        start = l[0]
    else:
        start = 500000000
    for i in range(1,n):
        if l[i] != -999999999:
            if start-l[i] >= x:
                cntmax += 1
            start = l[i]
        else:
            if start-x>= -500000000:
                start -= x
                cntmax += 1
            else:
                start = 500000000
    # cntmin
    if l[0] != -999999999:
        start = l[0]
    else:
        start = -500000000
    for i in range(1,n):
        if l[i] != -999999999:
            if start-l[i] >= x:
                cntmin += 1
            start = l[i]
        else:
            start = max(-500000000,start - x + 1)
    print(cntmax,cntmin)
if __name__ == "__main__":
    main()