题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
/** * struct ListNode { * int val; * struct ListNode *next; * ListNode(int x) : val(x), next(nullptr) {} * }; */ class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @param m int整型 * @param n int整型 * @return ListNode类 */ ListNode* reverseBetween(ListNode* head, int m, int n) { // write code here ListNode* empty_node = new ListNode(-1); empty_node->next = head; //取翻转起始节点前一个 ListNode* pre = empty_node; for(int i = 0;i < m - 1;i++) { pre = pre->next; } ListNode *beginNode = pre->next; // 取翻转终止节点后一个 ListNode *endNode = pre; for(int i = 0;i < n - m + 1; i++) { endNode = endNode->next; } ListNode* succ = endNode->next; endNode->next = nullptr; reverseList(beginNode); pre->next = endNode; beginNode->next = succ; return empty_node->next; } ListNode* reverseList(ListNode* head) { ListNode* cur = head; ListNode* pre = nullptr; while (cur) { ListNode* next = cur->next; cur->next = pre; pre = cur; cur = next; } return pre; } };