题解 | #牛牛的金币#
牛牛的金币
https://www.nowcoder.com/practice/35d8e3e569dc49f2a1018d1dc9186998
#include <stdio.h> int main() { int x, x1, y, y1; scanf("%d %d",&x,&y); scanf("%d %d",&x1,&y1); int upAndDown = y1 - y; int leftAndRight = x1 - x; switch (upAndDown) { case 1: printf("u"); return 0; case -1: printf("d"); return 0; } switch (leftAndRight) { case 1: printf("r"); return 0; case -1: printf("l"); return 0; } return 0; }