题解 | #牛牛的金币#
牛牛的金币
https://www.nowcoder.com/practice/35d8e3e569dc49f2a1018d1dc9186998
#include <stdio.h>
int main() {
int x, x1, y, y1;
scanf("%d %d",&x,&y);
scanf("%d %d",&x1,&y1);
int upAndDown = y1 - y;
int leftAndRight = x1 - x;
switch (upAndDown)
{
case 1:
printf("u");
return 0;
case -1:
printf("d");
return 0;
}
switch (leftAndRight)
{
case 1:
printf("r");
return 0;
case -1:
printf("l");
return 0;
}
return 0;
}
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