题解 | #牛牛的水杯#
牛牛的水杯
https://www.nowcoder.com/practice/c196c47c23394bf3bdd4f82a838df6bf
#include <stdio.h>
int main() {
double h = 0;
double r = 0;
double pi = 3.14;
scanf("%lf %lf", &h, &r);
double v = pi * r * r * h;
//求出一杯水的容积
int i = 0;
while (v * i <= 10000) {
i++;
}
//求出需要的杯数
printf("%d", i);
return 0;
}
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