题解 | #跳台阶扩展问题#

class Solution {
  public:
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     *
     * @param number int整型
     * @return int整型
     */
    int jumpFloorII(int number) {
        // write code here
        static int n = number;
        if (number == 0) {
            return 1;
        }
        if (number < 0) {
            return 0;
        }
        int count = 0;
        for (int i = 1; i <= n; ++i) {
            count += jumpFloorII(number - i);
        }
        return count;
    }
};