题解 | #字符串的反码#用25减去ASCII码就行
字符串的反码
https://www.nowcoder.com/practice/01b7dae14d1b464db5f9259e90d9a35e
s = input()
for c in s:
if c.isalpha():
if c.isupper():
print(chr(ord("A") + 25 - (ord(c) - ord("A"))), end="")
else:
print(chr(ord("a") + 25 - (ord(c) - ord("a"))), end="")
else:
print(c, end="")
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