题解 | #字典树的实现#
字典树的实现
https://www.nowcoder.com/practice/7f8a8553ddbf4eaab749ec988726702b
#include <iostream> #include <vector> #include <string> using namespace std; struct TrieNode { int pass; int end; vector<TrieNode*> nexts; TrieNode() :pass(0),end(0),nexts(26,nullptr) {}; }; class Trie { public: Trie() { root = new TrieNode(); } ~Trie() { freeTrie(root); } void insert(const string& word) { TrieNode* node = root; node->pass++; for(auto ch : word) { int path = ch - 'a'; if(path < 0 || path >= 26) return; if(node->nexts[path] == nullptr) { node->nexts[path] = new TrieNode(); } node = node->nexts[path]; node->pass++; } node->end++; } void erase(const string& word) { if(search(word) > 0) { TrieNode* node = root; node->pass--; for(auto ch : word) { int path = ch - 'a'; if(path < 0 || path >= 26) return ; if(--node->nexts[path]->pass == 0) { delete node->nexts[path]; node->nexts[path] = nullptr; return; } node = node->nexts[path]; } node->end--; } } int search(const string& word) { TrieNode* node = root; for(auto ch : word) { int path = ch - 'a'; if(path < 0 || path >=26 || node->nexts[path] == nullptr) { return 0; } node = node->nexts[path]; } return node->end ; } int prefixNumber(string pre) { TrieNode* node = root; for(auto ch : pre) { int path = ch - 'a'; if(path < 0 || path >= 26 || node->nexts[path] == nullptr) { return 0; } node = node->nexts[path]; } return node->pass; } private: void freeTrie(TrieNode* node) { if(node == nullptr) { return; } for(TrieNode* next : node->nexts) { freeTrie(next); } delete node; } private: TrieNode* root; }; int main() { int op = 0; string str; int n = 0; while(cin >> n) { Trie trie; while(n--) { cin>>op>>str; switch(op) { case 1: trie.insert(str); break; case 2: trie.erase(str); break; case 3: cout << (trie.search(str) > 0 ? "YES" : "NO")<<endl; break; case 4: cout << trie.prefixNumber(str) <<endl; break; } } } } // 64 位输出请用 printf("%lld")