题解 | #最短路径问题#
最短路径问题
https://www.nowcoder.com/practice/e372b623d0874ce2915c663d881a3ff2
//依然有点懵 #include <iostream> #include <climits> #include <vector> #include <cstring> #include <queue> using namespace std; const int INF=INT_MAX; struct Point { int id; int distance; bool operator<(const Point& p)const//放到优先队列里的元素自动排序 { return distance>p.distance; } Point(int i,int d) { id=i; distance=d; } }; struct Edge { int to; int distance; int cost; Edge(int t,int d,int c) { to=t; distance=d; cost=c; } }; vector<Edge> graph[1001];//向量类似高级数组,每个点里存它的所有Edge int dis[1001]; int cost[1001]; void Dijkstra(int s) { priority_queue<Point> q; dis[s]=0; cost[s]=0; q.push(Point(s,0)); while(!q.empty()) { int u=q.top().id; q.pop(); for(int i=0;i<graph[u].size();i++)//每个点都是自己vector数组从最先的位置(0)开始存 { int v=graph[u][i].to; int d=graph[u][i].distance; int c=graph[u][i].cost; if(dis[u]+d<dis[v]||((dis[u]+d==dis[v])&&(cost[u]+c<cost[v]))) { dis[v]=dis[u]+d; cost[v]=cost[u]+c; q.push(Point(v,dis[v])); } } } } int main() { int n,m; while (cin >> n>>m) { if(n==0&&m==0)break; memset(graph,0,sizeof(graph)); fill(dis,dis+1001,INF); fill(cost,cost+1001,INF); for(int i=1;i<=m;i++) { int from,to,d,c; cin>>from>>to>>d>>c; graph[from].push_back(Edge(to,d,c));//??每个点可能有多条连线啊 graph[to].push_back(Edge(from,d,c)); } int s,t; cin>>s>>t; Dijkstra(s); cout<<dis[t]<<" "<<cost[t]<<endl; } }