题解 | #记负均正#

#include <iostream>
using namespace std;

int main() {
    int n,num;
    int cnt = 0;
    double m = 0, sum = 0;
    cin >> n;
    while (n--){
        cin >> num;
        if (num < 0){
            cnt++;
        }
        else if (num > 0){
            sum += num;
            m++;
        }
        else{

        }
    }
    cout << cnt << " ";
    if (m !=0)
    printf("%0.1f", sum / m);
    else
    printf("%0.1f", sum);

    
}