题解 | #查找输入整数二进制中1的个数#

#include <iostream>
using namespace std;

int main() 
{
    long n;
    while (cin >> n){
        int cnt = 0;
        while (n != 0){
            if (n % 2 != 0){
                cnt++;
            }
            n = n/2;
        }
      
        cout << cnt <<endl;
    }
    
    return 0;
}