题解 | #购物单#
购物单
https://www.nowcoder.com/practice/f9c6f980eeec43ef85be20755ddbeaf4
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int main() {
int N, m; //N表示总钱数,m表示可购买的物品的个数
cin >> N >> m;
vector<int> prices(m);
vector<int> importance(m);
vector<int> master(m);
for (int i = 0; i < m; ++i) {
cin >> prices[i] >> importance[i] >> master[i];
}
//input
vector<vector<int>> prices_m(m);
vector<vector<int>> importance_m(m);
int ms_num = 0;
for (int i = 0; i < m; i++) {
if (master[i] == 0) {
ms_num++;
prices_m[i].push_back(prices[i]);
importance_m[i].push_back(importance[i]* prices[i]);
}
}
for (int i = 0; i < m; i++) {
int mst = master[i];
if (mst != 0) {
vector<int> p_buff = prices_m[mst - 1];
for (int p : p_buff) {
prices_m[mst - 1].push_back(p + prices[i]);
}
;
vector<int> im_buff = importance_m[mst - 1];
for (int im : im_buff) {
importance_m[mst - 1].push_back(im + importance[i]* prices[i]);
}
}
}
vector<int> dp(N + 1);
vector<int> dp_buff(N + 1);
for (int i = 0; i < m; ++i) {
for (int j = 0; j < N + 1; ++j) {
int idx_buff;
int imp_buff;
vector<int> value;
value.push_back(dp[j]);
for (int k = 0; k < prices_m[i].size(); k++) {
if (j >= prices_m[i][k])
{
idx_buff = j - prices_m[i][k];
imp_buff = importance_m[i][k];
value.push_back(dp_buff[idx_buff] + imp_buff);
}
}
dp[j] = *max_element(value.begin(), value.end());
}
dp_buff = dp;
}
//process
cout << dp[N];
cin.get();
//output
}
// 64 位输出请用 printf("%lld")

