题解 | #数列的和#
数列的和
https://www.nowcoder.com/practice/fe19f8a78a5148018f4be53ae9b5e11e
#include <stdio.h>
#include<math.h>
int main() {
int m = 0;
int n = 0;
while (~scanf("%d %d", &n, &m)) {
double num = (double)n;
double sum = (double)n;
for (int i = 1; i < m; i++) {
sum += sqrt((double)num);
num = sqrt(num);
}
printf("%.2lf\n", sum);
}
return 0;
}
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