题解 | #链表中环的入口结点#
链表中环的入口结点
https://www.nowcoder.com/practice/253d2c59ec3e4bc68da16833f79a38e4
/**
* struct ListNode {
* int val;
* struct ListNode *next;
* };
*/
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param pHead ListNode类
* @return ListNode类
*/
struct ListNode* EntryNodeOfLoop(struct ListNode* pHead )
{
if( pHead == NULL)
return NULL ;
// write code here
struct ListNode *fast = pHead;
struct ListNode *slow = pHead;
while(fast && fast -> next)
{
fast = fast -> next -> next;
slow = slow -> next;
if(fast == slow)
break;
} //判断链表是否有环
//如果链表循环到链表尾部而结束,则无环
if(fast == NULL || fast -> next == NULL)
return NULL;
//找入环节点
slow = pHead;
while (slow != fast)
{
slow = slow->next;
fast = fast->next;
}
return slow;
}