题解 | #链表中环的入口结点#
链表中环的入口结点
https://www.nowcoder.com/practice/253d2c59ec3e4bc68da16833f79a38e4
/** * struct ListNode { * int val; * struct ListNode *next; * }; */ /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param pHead ListNode类 * @return ListNode类 */ struct ListNode* EntryNodeOfLoop(struct ListNode* pHead ) { if( pHead == NULL) return NULL ; // write code here struct ListNode *fast = pHead; struct ListNode *slow = pHead; while(fast && fast -> next) { fast = fast -> next -> next; slow = slow -> next; if(fast == slow) break; } //判断链表是否有环 //如果链表循环到链表尾部而结束,则无环 if(fast == NULL || fast -> next == NULL) return NULL; //找入环节点 slow = pHead; while (slow != fast) { slow = slow->next; fast = fast->next; } return slow; }