题解 | #包含min函数的栈#
包含min函数的栈
https://www.nowcoder.com/practice/4c776177d2c04c2494f2555c9fcc1e49
# -*- coding:utf-8 -*-
s = []
class Solution:
def push(self, node):
# write code here
s.append(node)
def pop(self):
# write code here
return s.pop()
def top(self):
# write code here
return s[-1]
def min(self):
# write code here
return min(s)
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