题解 | #计算某字符出现次数#

#include <stdio.h>

int main() {
    char str[5000];
    char c;
    int i = 0;
    int count = 0;

    gets(str);

    c = getchar();
    if ( c >= 'a' && c <= 'z' ) {
        while (str[i] != '\0') {
            if (str[i] == c || str[i] == (c - 'a' + 'A')) {
                count++;
            }
            i++;
        }
    } else if (c >= 'A' && c <= 'Z') {
        while (str[i] != '\0') {
            if (str[i] == c || str[i] == (c - 'A' + 'a')) {
                count++;
            }
            i++;
        }
    } else {
        while (str[i] != '\0') {
            if (str[i] == c) {
                count++;
            }
            i++;
        }
    }

    printf("%d", count);

    return 0;
}