题解 | #特殊乘法#
特殊乘法
https://www.nowcoder.com/practice/a5edebf0622045468436c74c3a34240f
#include <bits/stdc++.h>
using namespace std;
int main(){
string a,b;
while(cin >> a >> b){
int alen = a.length();
int blen = b.length();
int count = 0;
for(int i = 0 ;i<alen;i++){
for(int j = 0 ; j < blen;j++){
count = count + (a[i]-'0') * (b[j]-'0');
}
}
cout << count << endl;
}
}
