题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
import java.util.*; /* * public class ListNode { * int val; * ListNode next = null; * public ListNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @param m int整型 * @param n int整型 * @return ListNode类 */ ListNode preHead = null; ListNode lastTail = null; public ListNode reverseBetween (ListNode head, int m, int n) { ListNode dummy = new ListNode(-1); ListNode pre = dummy; dummy.next = head; int current = 0; // 找到左节点 while (current < m - 1) { pre = pre.next; current++; } preHead = pre; ListNode currentTail = reverseLinkedList(pre.next, m, n); currentTail.next = lastTail; return dummy.next; } public ListNode reverseLinkedList(ListNode head, int current, int n) { if (current == n) { lastTail = head.next; return head; } ListNode currentPre = reverseLinkedList(head.next, current + 1, n); if (current == n - 1) { preHead.next = currentPre; } currentPre.next = head; return head; } }
采用递归方法