题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
import java.util.*;
/*
* public class ListNode {
* int val;
* ListNode next = null;
* public ListNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @param m int整型
* @param n int整型
* @return ListNode类
*/
ListNode preHead = null;
ListNode lastTail = null;
public ListNode reverseBetween (ListNode head, int m, int n) {
ListNode dummy = new ListNode(-1);
ListNode pre = dummy;
dummy.next = head;
int current = 0;
// 找到左节点
while (current < m - 1) {
pre = pre.next;
current++;
}
preHead = pre;
ListNode currentTail = reverseLinkedList(pre.next, m, n);
currentTail.next = lastTail;
return dummy.next;
}
public ListNode reverseLinkedList(ListNode head, int current, int n) {
if (current == n) {
lastTail = head.next;
return head;
}
ListNode currentPre = reverseLinkedList(head.next, current + 1, n);
if (current == n - 1) {
preHead.next = currentPre;
}
currentPre.next = head;
return head;
}
}
采用递归方法
查看6道真题和解析