题解 | #平均活跃天数和月活人数#

平均活跃天数和月活人数

https://www.nowcoder.com/practice/9e2fb674b58b4f60ac765b7a37dde1b9

select date_format(submit_time,'%Y%m') as month
,round((count(distinct uid, day(submit_time)))/count(distinct uid),2) as avg_active_days
,count(distinct uid) as mau
from exam_record
where submit_time is not null 
and year(submit_time) = 2021
group by date_format(submit_time,'%Y%m');

难点:1、算月用户活跃总天数。count(distinct uid,day(submit_time)) 即计算每位用户每天的行数。思考:这里可以用sum吗?

易错:括号;函数写法,没写对的时候不会显示颜色。。

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