题解 | #求最大连续bit数#
求最大连续bit数
https://www.nowcoder.com/practice/4b1658fd8ffb4217bc3b7e85a38cfaf2
n = int(input())
list1 = list(bin(n)[2:]) # 转换成二进制字符串0b开头，oct()八进制0o开头，hex()十六进制 0x开头
length = len(list1)
def islianxu(s):
for i in s:
if i != '1':
return False
return True
max = 1
for i in range(length):
for j in range(length):
if islianxu(list1[i:j+1]):
if max < j - i + 1:
max = j - i + 1
print(max)
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