题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
def func():
n = int(input())
nums = list(map(int, input().split()))
k = int(input())
print(nums[-k]) # 倒数第k个,是负数
try:
while True:
func()
except EOFError:
pass
投递小米集团等公司10个岗位
