立志重刷代码随想录60天冲冲冲!!——第二十三天
39. 组合总和
class Solution { public: vector<vector<int>> res; vector<int> path; int sum = 0; void backtracking(vector<int> candidates, int target, int startIdx) { if (sum == target) { res.push_back(path); return; } else if (sum > target) { // sum大于target也需要返回!!! return; } for (int i = startIdx; i < candidates.size(); i++) { int num = candidates[i]; path.push_back(num); sum += num; backtracking(candidates, target, i); // 不需要加一 sum -= num; path.pop_back(); } return; } vector<vector<int>> combinationSum(vector<int>& candidates, int target) { backtracking(candidates, target, 0); return res; } };
40.组合总和II
class Solution { public: vector<vector<int>> res; vector<int> path; int sum = 0; void backtracking(vector<int> candidates, int target, int startIdx, vector<bool>& used) { if (sum > target) return; else if (sum == target) { res.push_back(path); return; } for (int i = startIdx; i < candidates.size(); i++) { // used[i - 1] == true,说明同一树枝candidates[i - 1]使用过 // used[i - 1] == false,说明同一树层candidates[i - 1]使用过 if (i > 0 && candidates[i] == candidates[i - 1] && used[i - 1] == false) continue; int num = candidates[i]; path.push_back(num); sum += num; used[i] = true; backtracking(candidates, target, i + 1, used); used[i] = false; sum -= num; path.pop_back(); } return; } vector<vector<int>> combinationSum2(vector<int>& candidates, int target) { // 初始化bool数组 vector<bool> used(candidates.size(), false); sort(candidates.begin(), candidates.end()); backtracking(candidates, target, 0, used); return res; } };
131.分割回文串
s.substr(起始索引,个数)
class Solution { public: vector<vector<string>> res; vector<string> path; bool isCycleTring(string& s, int start, int end) { for (int i = start, j = end; i < j; i++, j--) { if (s[i] != s[j]) return false; } return true; } void backtracking(string s, int startIdx) { if (s.size() == startIdx) { res.push_back(path); return; } for (int i = startIdx; i < s.size(); i++) { if (isCycleTring(s, startIdx, i) == true) { string str = s.substr(startIdx, i - startIdx + 1); //s.substr(起始索引,个数); path.push_back(str); } else continue; backtracking(s, i + 1); path.pop_back(); } return; } vector<vector<string>> partition(string s) { backtracking(s, 0); return res; } };
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