题解 | #整数与IP地址间的转换#按照输入格式粗暴分类
整数与IP地址间的转换
https://www.nowcoder.com/practice/66ca0e28f90c42a196afd78cc9c496ea
#include <bitset>
#include <iostream>
#include <string>
using namespace std;
int main() {
string str1;
string str2;
int num=0;
long ans_out1=0;
getline(cin, str1);
getline(cin, str2);
string temp_string=str1;
string string_out;
int total_len=str1.size();
for (int temp=0; temp<4; temp++)
{
string temp_answer;
total_len=temp_string.size();
int temp_num=temp_string.find('.');
temp_answer=temp_string.substr(0,temp_num);
temp_string=temp_string.substr(temp_num+1,total_len-temp_num-1);
double num_for_answer=1;
for(int i=3;i>temp;i--)
num_for_answer=num_for_answer*256;
ans_out1=ans_out1+stoi(temp_answer)*num_for_answer;
}
cout<<ans_out1<<endl;
long total_num=stol(str2);
long temp_num2=total_num;
for (int temp=0; temp<4; temp++)
{
int answer_num=0;
long num_for_answer=1;
if(temp<3)
{
for(int i=3;i>temp;i--)
num_for_answer=num_for_answer*256;
}
answer_num=temp_num2/num_for_answer;
string_out=string_out+to_string(answer_num);
if(temp!=3)
string_out=string_out+".";
temp_num2=temp_num2%num_for_answer;
}
cout<<string_out<<endl;
}
// 64 位输出请用 printf("%lld")
