题解 | #提取不重复的整数#

#include <iostream>
#include <vector>

using namespace std;

int main() {
    int a, b=0;
    vector<int> array(10,0);

    cin >> a;
    while((a/10 > 0)||(a%10 > 0)){
        if (array[a%10] == 0)
        {
            //桶排序实现
            array[a%10] = 1;
            b = b *10 + a%10;
        }
        a/=10;
    }
  
    cout << b << endl;
    return 0;
}