字符串结尾判断 | HJ99 自守数
#最优解
while True:
try:
n = int(input())
num =0
for i in range(n):
b = str(i**2)
if b.endswith(str(i)):
num+=1
print(num)
except:
break
# 我的代码
while True:
try:
n = int(input())
cnt = 0
for i in range(n+1):
i_len = len(str(i))
if str(i**2)[i_len*(-1):] == str(i):
cnt += 1
print(cnt)
except:
break
华为笔试刷题 文章被收录于专栏
高质量题: 1~40:HJ16,HJ22,HJ24,HJ26,HJ27,HJ28,HJ35,HJ37,HJ39; 40~80:HJ41,HJ42,HJ43,HJ44,HJ48,HJ50,HJ52,HJ53,HJ57,HJ61,HJ63,HJ64,HJ70,HJ71,HJ74,HJ77; 80~108:HJ82,HJ85,HJ88,HJ89,HJ93,HJ95,HJ98,HJ103,HJ107
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