递归 | HJ93 数组分组

# 最优解
def dfs(three, five, other):
    if not other:
        if sum(three) == sum(five):
            return True
        else:
            return False
    if dfs(three+other[:1], five, other[1:]):
        return True
    if dfs(three, five+other[:1], other[1:]):
        return True
 
while True:
    try:
        n, nums = int(input()), list(map(int, input().split()))
        three, five, other = [], [], []
        for num in nums:
            if num % 3 == 0:
                three.append(num)
            elif num % 5 == 0:
                five.append(num)
            else:
                other.append(num)
        if dfs(three, five, other):
            print ('true')
        else:
            print ('false')
    except:
        break

华为笔试刷题 文章被收录于专栏

高质量题: 1~40:HJ16,HJ22,HJ24,HJ26,HJ27,HJ28,HJ35,HJ37,HJ39; 40~80:HJ41,HJ42,HJ43,HJ44,HJ48,HJ50,HJ52,HJ53,HJ57,HJ61,HJ63,HJ64,HJ70,HJ71,HJ74,HJ77; 80~108:HJ82,HJ85,HJ88,HJ89,HJ93,HJ95,HJ98,HJ103,HJ107

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