题解 | #二进制中1的个数#
二进制中1的个数
https://www.nowcoder.com/practice/8ee967e43c2c4ec193b040ea7fbb10b8
class Solution {
public:
int NumberOf1(int n) {
int result = 0;
while (n != 0) {
result++;
n = n & (n - 1); // 清除最低位的1
}
return result;
}
};
