题解 | #等差数列#4行代码
等差数列
https://www.nowcoder.com/practice/f792cb014ed0474fb8f53389e7d9c07f
#include <stdio.h> int main() { int num; scanf("%d", &num); int ret = num * 2 + num * (num - 1) * 3 / 2; printf("%d", ret); return 0; }
等差数列
https://www.nowcoder.com/practice/f792cb014ed0474fb8f53389e7d9c07f
#include <stdio.h> int main() { int num; scanf("%d", &num); int ret = num * 2 + num * (num - 1) * 3 / 2; printf("%d", ret); return 0; }
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