题解 | #打家劫舍(二)#
打家劫舍(二)
https://www.nowcoder.com/practice/a5c127769dd74a63ada7bff37d9c5815
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# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
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# @param nums int整型一维数组
# @return int整型
#
class Solution:
def sub_rob(self , nums: List[int]) -> int:
# write code here
n = len(nums)
if n == 1:
return nums[0]
if n == 2:
return max(nums[0], nums[1])
dp = [0 for _ in range(n)]
dp[0] = nums[0]
dp[1] = max(nums[0], nums[1])
for i in range(2, n):
dp[i] = max(dp[i-1], dp[i-2]+nums[i])
return dp[n-1]
def rob(self, nums: List[int]) -> int:
# write code here
n = len(nums)
if n == 1:
return nums[0]
if n == 2:
return max(nums[0], nums[1])
if n == 3:
return max(nums[0], nums[1], nums[2])
nums_0 = nums[0: n-1]
nums_1 = nums[1: n]
res_0 = self.sub_rob(nums_0)
res_1 = self.sub_rob(nums_1)
return max(res_0, res_1)
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