题解 | #简单密码#

def transform_password(pw):
    # 九键键盘映射
    keypad = {
        "a": "2",
        "b": "2",
        "c": "2",
        "d": "3",
        "e": "3",
        "f": "3",
        "g": "4",
        "h": "4",
        "i": "4",
        "j": "5",
        "k": "5",
        "l": "5",
        "m": "6",
        "n": "6",
        "o": "6",
        "p": "7",
        "q": "7",
        "r": "7",
        "s": "7",
        "t": "8",
        "u": "8",
        "v": "8",
        "w": "9",
        "x": "9",
        "y": "9",
        "z": "9",
    }

    # 变换密码
    transformed_pw = ""
    for c in pw:
        if c.isalpha():  # 如果是字母
            if c.isupper():  # 大写字母转小写并移位
                c = c.lower()
                if c == "z":
                    transformed_pw += "a"  # 特殊处理Z
                else:
                    transformed_pw += chr(ord(c) + 1)  # 往后移一位
            else:  # 小写字母转换为数字
                transformed_pw += keypad.get(c, c)  # 使用get方法处理不在映射中的字符
        else:
            # 数字和其它符号不变
            transformed_pw += c

    return transformed_pw


# 读取输入并输出变换后的密码
if __name__ == "__main__":
    passwords = input().split()  # 假设输入可以有多个密码，以空格分隔
    for pw in passwords:
        print(transform_password(pw))

定义了一个transform_password函数，它接受一个密码字符串作为输入，并返回变换后的密码字符串。函数内部使用了一个字典keypad来映射小写字母到对应的九键键盘数字。对于大写字母，函数将其转换为小写，然后根据规则进行移位。数字和其他符号保持不变。