题解 | #二叉树的前序遍历#
二叉树的前序遍历
https://www.nowcoder.com/practice/5e2135f4d2b14eb8a5b06fab4c938635
import java.util.*; /* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * public TreeNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param root TreeNode类 * @return int整型一维数组 */ private List<Integer> valueList = new ArrayList<>(); private Stack<TreeNode> stack = new Stack<>(); private TreeNode root = new TreeNode(1); public void createBiTree() { TreeNode node1 = new TreeNode(2); root.right = node1; TreeNode node2 = new TreeNode(3); node1.left = node2; } public TreeNode getRoot() { return root; } public int[] preorderTraversal (TreeNode root) { preorderTraversalByLoop(root); //preOrderTraversalRecursively(root); return valueList.stream().mapToInt(i->i).toArray(); } private void preorderTraversalByLoop (TreeNode node) { // write code here stack.push(node); while(!stack.empty()) { node = stack.pop(); while(null != node) { //调用结点的操作函数 appendNode(node); if(null != node.right) { //如果该结点有右孩子,右孩子进栈 stack.push(node.right); } //一直指向根结点最后一个左孩子 node = node.left; } } } private void preOrderTraversalRecursively(TreeNode node){ if (null != node) { appendNode(node);//调用操作结点数据的函数方法 preOrderTraversalRecursively(node.left);//访问该结点的左孩子 preOrderTraversalRecursively(node.right);//访问该结点的右孩子 } //如果结点为空,返回上一层 return; } public void appendNode(TreeNode node) { System.out.println("node value=" + node.val); valueList.add(node.val); } public static void main(String[] args) { Solution solution = new Solution(); solution.createBiTree(); solution.preorderTraversal(solution.getRoot()); } }