题解 | #有效括号序列#
有效括号序列
https://www.nowcoder.com/practice/37548e94a270412c8b9fb85643c8ccc2
class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param s string字符串 * @return bool布尔型 */ bool isValid(string s) { // write code here if (s.size() == 0) return true; stack<char> myStack; for (int i = 0; i < s.size(); i++) { if (s[i] == '(' || s[i] == '{' || s[i] == '[') { myStack.push(s[i]); } if (s[i] == ')') { if (myStack.empty()) return false; else { if ('(' == myStack.top()) { myStack.pop(); } } } if (s[i] == '}') { if (myStack.empty()) return false; else { if ('{' == myStack.top()) { myStack.pop(); } } } if (s[i] == ']') { if (myStack.empty()) return false; else { if ('[' == myStack.top()) { myStack.pop(); } } } } if (myStack.empty()) return true; else return false; } };