题解 | #数组元素反转#

#include <iostream>
using namespace std;

int main() {

    int arr[6] = { 0 };

    int len = sizeof(arr) / sizeof(int);

    for (int i = 0; i < len; i++) {
        cin >> arr[i];
    }

    cout << "[";
    for (int i = 0; i < len; i++) {
        if (i == len - 1) {
            cout << arr[i] << "]" << endl;
            break;
        }
        cout << arr[i] << ", ";
    }

    // write your code here......
    int h = 0; // 修改初始值为数组长度减一，从最后一个元素开始
    int mix = 0;
    int r = 5; // 保持不变，因为我们要用它来指向当前元素
    while (h < r) {
        mix = arr[h];
        arr[h] = arr[r];
        arr[r] = mix;
        h ++;
        r --;
    }

    cout << "[";
    for (int i = 0; i < len; i++) {
        if (i == len - 1) {
            cout << arr[i] << "]" << endl;
            break;
        }
        cout << arr[i] << ", ";
    }

    return 0;
}