题解 | #实现二叉树先序,中序和后序遍历#
实现二叉树先序,中序和后序遍历
https://www.nowcoder.com/practice/a9fec6c46a684ad5a3abd4e365a9d362
import java.util.*;
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* public TreeNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param root TreeNode类 the root of binary tree
* @return int整型二维数组
*/
public int[][] threeOrders (TreeNode root) {
// write code here
List<Integer> list1 = new ArrayList<>();
List<Integer> list2 = new ArrayList<>();
List<Integer> list3 = new ArrayList<>();
xianxu(root, list1);
zhongxu(root, list2);
houxu(root, list3);
int[][] res = new int[3][list1.size()];
for (int i = 0; i < list1.size(); i++) {
res[0][i] = list1.get(i);
res[1][i] = list2.get(i);
res[2][i] = list3.get(i);
}
return res;
}
private void xianxu(TreeNode root, List<Integer> list){
if (root == null) {
return;
}
list.add(root.val);
xianxu(root.left, list);
xianxu(root.right, list);
}
private void zhongxu(TreeNode root, List<Integer> list){
if (root == null) {
return;
}
zhongxu(root.left, list);
list.add(root.val);
zhongxu(root.right, list);
}
private void houxu(TreeNode root, List<Integer> list){
if (root == null) {
return;
}
houxu(root.left, list);
houxu(root.right, list);
list.add(root.val);
}
}

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