题解 | #求 1 - n 之间偶数的和#
求 1 - n 之间偶数的和
https://www.nowcoder.com/practice/03df7fa0950046a9ba564b4438f918a3
#include <iostream>
using namespace std;
int main() {
int n;
cin >> n;
int sum = 0;
// write your code here......
for(int i=2;i<=n;i+=2)
{
sum=(i/2)*((i/2)+1);
}
cout << sum << endl;
return 0;
}
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