题解 | #最长公共子序列(一)#
最长公共子序列(一)
https://www.nowcoder.com/practice/672ab5e541c64e4b9d11f66011059498
#include <iostream> #include <cstring> #include <vector> using namespace std; int n, m; string s1, s2; int main() { cin >> n >> m >> s1 >> s2; vector<vector<int>> dp(n+1, vector<int>(m + 1, 0)); for (int i = 1; i <=n; i++) for (int j = 1; j <=m; j++) { if (s1[i-1] == s2[j-1]) dp[i][j] = dp[i - 1][j - 1] + 1; else dp[i][j] = max(dp[i - 1][j - 1], max(dp[i][j - 1], dp[i - 1][j])); } cout<<dp[n][m]; } // 64 位输出请用 printf("%lld")