题解 | #旋转数组的最小数字#

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param nums int整型一维数组 
# @return int整型
#
class Solution:
    def minNumberInRotateArray(self , nums: List[int]) -> int:
        # write code here
        left,right = 0,len(nums)-1
        while left<right:
            mid = (left+right)//2
            if nums[mid]>nums[right]:
                left = mid +1
            elif nums[mid]==nums[left]:
                right = right-1
            else:
                right = mid
        return nums[left]