题解 | #提取不重复的整数#

a = int(input())
b = str(a)
length = len(b)
L = []
for i in range(length-1,-1,-1):
    c = int(a / (10**i))
    a = a - c * (10**i)
    L.append(c)
L.reverse()
L2 = []
for i in L:
    if i not in L2:
        L2.append(i)
n = len(L2)-1
ans = 0
for i in L2:
    ans += i * (10**n)
    if n >= 0:
        n -= 1
print(ans)