题解 | #提取不重复的整数#
提取不重复的整数
https://www.nowcoder.com/practice/253986e66d114d378ae8de2e6c4577c1
a = int(input())
b = str(a)
length = len(b)
L = []
for i in range(length-1,-1,-1):
c = int(a / (10**i))
a = a - c * (10**i)
L.append(c)
L.reverse()
L2 = []
for i in L:
if i not in L2:
L2.append(i)
n = len(L2)-1
ans = 0
for i in L2:
ans += i * (10**n)
if n >= 0:
n -= 1
print(ans)
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