题解 | #质数因子#
质数因子
https://www.nowcoder.com/practice/196534628ca6490ebce2e336b47b3607
a = int(input())
# b = int(a/2)
L = []
def cul(a,L):
if a==1:
return
for i in range(2,int(a**(1/2))+1):
if a % i == 0 and a != 1:
L.append(i)
next =int( a / i)
_,a = cul(next,L)
break
return L,a
L,b = cul(a,L)
if b != 1:
L.append(b)
print(" ".join(str(i) for i in L))
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