题解 | #日期差值#
日期差值
https://www.nowcoder.com/practice/ccb7383c76fc48d2bbc27a2a6319631c
#include <iostream>
using namespace std;
int M[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
bool isrun(int y){
if(y%400==0||(y%4==0&&y%100!=0)) return true;
return false;
}
void add(int& y,int& m,int& d){
if(isrun(y)) M[2]=29;else M[2]=28;
d++;if(d>M[m]) {d=1;m++;if(m>12){m=1;y++;}}
}
int main() {
string a, b;int ans=0;
cin >> a >> b;if(a>b) swap(a,b);
int y1=stoi(a.substr(0,4));
int m1=stoi(a.substr(4,2)); int d1=stoi(a.substr(6,2));
int y2=stoi(b.substr(0,4));
int m2=stoi(b.substr(4,2)); int d2=stoi(b.substr(6,2));
while(y1!=y2||m1!=m2||d1!=d2){
add(y1,m1,d1);ans++;
}
cout<<ans+1;
}
// 64 位输出请用 printf("%lld")
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